12

Math Analysis HL Paper 1 (May 2024, TZ2)

  1. [Maximum mark: 20]

(a) Let f(x)=(1ax)12f(x) = (1 - ax)^{-\frac{1}{2}}, where ax<1,a0ax < 1, a \neq 0. The nthn^{\text{th}} derivative of f(x)f(x) is denoted by f(n)(x),nZ+f^{(n)}(x), n \in \mathbb{Z}^+. Prove by induction that
f(n)(x)=an(2n1)!(1ax)2n+1222n1(n1)!,  nZ+.f^{(n)}(x) = \frac{a^n(2n-1)! \,(1-ax)^{-\frac{2n+1}{2}}}{2^{2n-1}(n-1)!},\; n \in \mathbb{Z}^+.

(b) By using part (a) or otherwise, show that the Maclaurin series for f(x)=(1ax)12f(x) = (1 - ax)^{-\frac{1}{2}} up to and including the x2x^2 term is 1+12ax+38a2x21 + \frac{1}{2}ax + \frac{3}{8}a^2x^2.

(c) Hence, show that (12x)12(14x)122+6x+19x22(1 - 2x)^{-\frac{1}{2}}(1 - 4x)^{-\frac{1}{2}} \approx \frac{2 + 6x + 19x^2}{2}.

(d) Given that the series expansion for (1ax)12(1 - ax)^{-\frac{1}{2}} is convergent for ax<1|ax| < 1, state the restriction which must be placed on xx for the approximation
(12x)12(14x)122+6x+19x22(1 - 2x)^{-\frac{1}{2}}(1 - 4x)^{-\frac{1}{2}} \approx \frac{2 + 6x + 19x^2}{2} to be valid.

(e) Use x=110x = \frac{1}{10} to determine an approximate value for 3\sqrt{3}. Give your answer in the form cd\frac{c}{d}, where c,dZ+c, d \in \mathbb{Z}^+.