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Math Analysis SL Paper 1 (November 2024, TZ2)

  1. [Maximum mark: 17]
    Consider a cylinder of radius 4r4r and height hh. A smaller cylinder of radius rr is removed from the centre to form a hollow cylinder. This is shown in the following diagram.
Figure region page 11
Figure region from page 11

All lengths are measured in centimetres.

The total surface area of the hollow cylinder, in cm², is given by SS.
The volume of the hollow cylinder, in cm³, is given by VV.

(a) Show that S=30πr2+10πrhS = 30\pi r^{2} + 10\pi r h. [3]

(b) The total surface area of the hollow cylinder is 240π240\pi cm².
Show that V=360πr45πr3V = 360\pi r - 45\pi r^{3}. [6]

(c) Find an expression for dVdr\dfrac{dV}{dr}. [2]

The hollow cylinder has its maximum volume when r=p23r = p\sqrt{\dfrac{2}{3}}, where pZ+p \in \mathbb{Z}^{+}.

(d) Find the value of pp. [3]

(e) Hence, find this maximum volume, giving your answer in the form qπ23q\pi\sqrt{\dfrac{2}{3}}, where qZ+q \in \mathbb{Z}^{+}. [3]