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Math Analysis HL Paper 1 (May 2025, TZ2)

  1. [Maximum mark: 19]

(a) Find the first four terms in the binomial expansion of 1+5x\sqrt{1 + 5x} in ascending powers of xx. [4]

Consider the expression (1+px)(1+qx)1(1 + px)(1 + qx)^{-1}, where p,qQp, q \in \mathbb{Q}.

(b) Find the expansion of (1+px)(1+qx)1(1 + px)(1 + qx)^{-1} in ascending powers of xx, up to and including the term in x2x^2. [3]

The expansions found in parts (a) and (b) are identical up to the first three terms, for a value of pp and a value of qq.

(c) Show that q=54q = \frac{5}{4}. [4]

(d) The expression 1+px1+qx\frac{1 + px}{1 + qx}, with p=154p = \frac{15}{4} and q=54q = \frac{5}{4}, can be used as an approximation for 1+5x\sqrt{1 + 5x} where x<15|x| < \frac{1}{5}.

(i) Hence, by finding a suitable value for xx, find the approximation for 1.2\sqrt{1.2} in the form mn\frac{m}{n}, where m,nZm, n \in \mathbb{Z}.

(ii) Now consider the approximation for 52\frac{\sqrt{5}}{2}. Explain why the approximation for 52\frac{\sqrt{5}}{2} is not as accurate as the approximation for 1.2\sqrt{1.2}. [6]