IB Chemistry SL Structure 1: Models of the particulate nature of matter questions

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Question 1

Paper 2Easy5 marks

A sample of chlorine is modelled as containing only the two isotopes shown in Figure 1. Use the mass numbers as the isotope masses when calculating the relative atomic mass.

34353637380102030405060708090100Mass number of chlorine isotopeRelative abundance / %75.8%24.2%
(a)

State the number of neutrons in 1737Cl{}^{37}_{17}\mathrm{Cl}

[1]
(b)

State where the electrons are found relative to the nucleus in a chlorine atom.

[1]
(c)

Explain why 1735Cl{}^{35}_{17}\mathrm{Cl} and 1737Cl{}^{37}_{17}\mathrm{Cl} are isotopes.

[1]
(d)

Using Figure 1, determine the relative atomic mass of the chlorine sample. Give your answer to 3 significant figures.

[2]

Question 2

Multiple choiceEasy1 mark

A sample contains 0.0400 mol0.0400\ \text{mol} of O2\mathrm{O_2} molecules. What is the number of oxygen atoms in the sample? Use NA=6.02×1023 mol−1N_\mathrm{A}=6.02\times10^{23}\ \text{mol}^{-1}

Show answer and explanation

Answer: C. Each O2\mathrm{O_2} molecule contains two oxygen atoms. Thus, 0.0400×6.02×1023×2=4.82×10220.0400\times6.02\times10^{23}\times2=4.82\times10^{22} oxygen atoms.

A: uses 0.00400 mol0.00400\ \text{mol} and counts O2\mathrm{O_2} molecules rather than oxygen atoms.
B: counts O2\mathrm{O_2} molecules but omits the two oxygen atoms in each molecule.
D: shifts the amount one place too high, using 0.400 mol0.400\ \text{mol}

Remember: multiply by the number of specified entities in each molecule when counting atoms.

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