Answer: D. Work on each segment is the force component along that segment multiplied by its length. The east and north components are 10.0cos30.0∘=8.66 N and 10.0sin30.0∘=5.00 N. Thus W=(8.66)(6.0)+(5.00)(8.0)=91.96 J, which is 92 J to two significant figures.
A: subtracts the northward contribution instead of adding it, giving 52−40=12 J.
B: includes only the work during the northward displacement, 40 J.
C: includes only the work during the eastward displacement, 52 J.
Remember: add the work contributions from successive displacements, including their signs.