IB Physics SL A.3 Work, energy and power questions

Answer: D. Work on each segment is the force component along that segment multiplied by its length. The east and north components are $10.0\cos30.0^\circ=8.66\ \text{N}$ and $10.0\sin30.0^\circ=5.00\ \text{N}$ Thus $W=(8.66)(6.0)+(5.00)(8.0)=91.96\ \text{J}$ which is $92\ \text{J}$ to two significant figures. A: subtracts the northward contribution instead of adding it, giving $52-40=12\ \text{J}$ B: includes only the work during the northward displacement, $40\ \text{J}$ C: includes only the work during the eastward displacement, $52\ \text{J}$ Remember: add the work contributions from successive displacements, including their signs.