IB Physics SL Theme A: Space, time and motion questions

Exam-style multiple choice and written questions with full markschemes. Check multiple choice answers straight away, or type, photograph or draw a written answer and get it marked.

Type
Multiple choiceWritten
Difficulty
EasyMediumHard

Question 1

Paper 2Easy9 marks

A cart moves along a straight track in the positive xx-direction. Figure 1 shows its velocity vv as a function of time tt At t=0t=0 the cart is at x=5.0 mx=5.0\ \mathrm{m}

012345678012345678t / sv / m s-1
(a)

State the velocity of the cart at t=4.0 st=4.0\ \mathrm{s}

[1]
(b)

Determine the acceleration of the cart between t=2.0 st=2.0\ \mathrm{s} and t=6.0 st=6.0\ \mathrm{s}

[2]
(c)

Calculate the displacement of the cart between t=0t=0 and t=2.0 st=2.0\ \mathrm{s}

[1]
(d)

Calculate the displacement of the cart between t=2.0 st=2.0\ \mathrm{s} and t=6.0 st=6.0\ \mathrm{s}

[2]
(e)

State the acceleration of the cart between t=6.0 st=6.0\ \mathrm{s} and t=8.0 st=8.0\ \mathrm{s}

[1]
(f)

Determine the position of the cart at t=6.0 st=6.0\ \mathrm{s} using your answers to (c) and (d).

[2]

Question 2

Multiple choiceHard1 mark

Blocks A, B and C, of masses 2.0 kg, 3.0 kg and 5.0 kg respectively, are in contact in that order on a horizontal track. A 50 N horizontal force pushes B to the right. Friction forces on A, B and C are 2.0 N, 5.0 N and 3.0 N respectively, all to the left. The blocks move together. What is the force exerted by C on B?

Show answer and explanation

Answer: B. For all three blocks, the resultant force is 50−2.0−5.0−3.0=40 N50-2.0-5.0-3.0=40\ \text{N} so their acceleration is 40/(2.0+3.0+5.0)=4.0 m s−240/(2.0+3.0+5.0)=4.0\ \text{m s}^{-2} to the right. For C, the contact force from B satisfies F−3.0=5.0(4.0)F-3.0=5.0(4.0) giving F=23 NF=23\ \text{N} to the right. The force exerted by C on B is equal in magnitude and opposite in direction: 23 N23\ \text{N} to the left.
A: uses mCa=20 Nm_Ca=20\ \text{N} as the contact force, omitting friction on C.
C: gives the force on C by B, not the equal-and-opposite force on B.
D: treats the resultant force on all three blocks as the force at the B–C contact.
Remember: interaction forces act on different bodies and are equal in magnitude and opposite in direction.

Question 3

Paper 2Easy6 marks

An electric winch raises a crate vertically at constant speed. Figure 1 shows the power transfers while the winch is operating.

input power, 150 Wuseful output power, 96 Wwinchdissipated power, 54 W
(a)

State the energy form supplied to the winch and the useful energy form gained by the crate.

[2]
(b)

Calculate the efficiency of the winch.

[2]
(c)

Calculate the useful energy transferred to the crate in 25 s at the operating conditions shown.

[2]

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