IB Biology SL Theme B: Form and function questions

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Question 1

Multiple choiceHard1 mark

A plant cell stores starch as represented in the figure. Each hexagon represents one α-glucose monomer; the diagram is schematic and not to scale. Which description correctly identifies P and Q and the structural basis of starch’s storage properties?

α-glucoseα-glucoseα-glucoseα-glucoseα-glucoseα-glucoseα-glucoseα-glucoseα-glucose monomersPQα-glucoseα-glucoseα-glucoseα-glucoseα-glucoseα-glucoseα-glucoseα-glucosestarch polymerα-glucoseα-glucoseα-glucoseα-glucoseα-glucoseα-glucoseα-glucoseα-glucoseα-glucose monomers
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Answer: C. In the figure, P joins separate α-glucose monomers into a starch polymer, while Q separates the polymer into monomers. Joining monomers by condensation releases water; hydrolysis uses water to break the polymer apart. Coiling and branching make the polymer compact, while its large molecular size makes it relatively insoluble.

A: reverses the direction of the two processes, so it assigns polymer breakdown to P and polymer building to Q.
B: identifies the processes correctly but reverses their water balance.
D: swaps the structural explanations: coiling and branching account for compactness, while large molecular size accounts for relative insolubility.

Remember: condensation builds glucose polymers and releases water; hydrolysis breaks them down and uses water.

Question 2

Multiple choiceMedium1 mark

Two polypeptides each contain 80 amino acids and the same number of each amino-acid type, but the amino acids are in different orders. Which statement correctly links this difference to a possible effect of a large pH change or high temperature?

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Answer: B. Polypeptides with the same amino-acid composition can differ when their amino acids are in a different order. A large pH change or high temperature could cause denaturation, changing protein structure.

A: treats composition as sufficient to identify a polypeptide, overlooking amino-acid order.
C: confuses a change in protein structure with a change in amino-acid sequence.
D: assumes structure cannot change unless the amino-acid order changes.

Remember: amino-acid order distinguishes polypeptides, while denaturation changes protein structure.

Question 3

Multiple choiceEasy1 mark

Solutes X and Y each have lower concentrations outside a cell than inside. Membrane protein P transports X into the cell, but not Y; this movement stops when ATP is unavailable. Which description best explains P’s action?

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Answer: D. The concentration of X is lower outside the cell, so inward movement is against its concentration gradient. P transports X but not Y, showing selectivity, and its activity depends on ATP. It therefore acts as a selective pump using ATP for active transport.

A: Confuses active transport with facilitated diffusion, which does not use ATP to move particles against a concentration gradient.
B: Reverses the observed direction of X transport.
C: Treats P as non-selective, although it transports X but not Y.
Remember: pumps use ATP to move specific particles against concentration gradients.

Question 4

Multiple choiceEasy1 mark

Following ultracentrifugation, a researcher tests separated cell components to relate their structures to their functions. Which component should be classified as an organelle?

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Answer: D. Organelles are discrete cell subunits adapted to perform specific functions; the plasma membrane is classified as an organelle.

A: treats the cytoplasm, which is not an organelle, as a discrete subunit.
B: confuses the cytoskeleton with an organelle; it is not classified as one.
C: treats the cell wall as an organelle, although it is not classified as one.
Remember: the plasma membrane is an organelle, but the cell wall, cytoskeleton and cytoplasm are not.

Question 5

Multiple choiceMedium1 mark

A signal forms a gradient across four adjacent regions of an early embryo. Gene G is expressed only where the signal concentration exceeds 6 arbitrary units. Cells expressing gene G differentiate into specialized cell type P; cells not expressing it differentiate into another type. Which outcome is predicted? [1 mark]

Embryo regionSignal concentration / arbitrary units
W8
X7
Y5
Z3
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Answer: C. Gene G is expressed only where the signal concentration exceeds 6 arbitrary units. Regions W and X have concentrations of 8 and 7, so their cells express gene G and differentiate into type P. Regions Y and Z are below the threshold and differentiate into another type.

A: considers only the region with the highest concentration, overlooking that X also exceeds the threshold.
B: reverses the effect of the signal by assigning type P to regions below the threshold.
D: assumes all regions have the same gene expression and fate despite their different signal concentrations.

Remember: a gradient can lead to different gene-expression patterns and cell fates in an early embryo.

Question 6

Multiple choiceEasy1 mark

During a spirometry investigation, a student takes a normal breath in and then inhales as much additional air as possible. Which lung volume is represented by the additional volume measured?

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Answer: B. Inspiratory reserve volume is the additional volume that can be inhaled after a normal inspiration.

A: confuses the additional inhalation with tidal volume, the volume moved during a normal breath.
C: reverses the direction; expiratory reserve volume is additional air exhaled after a normal expiration.
D: treats the additional volume as vital capacity, which is the volume moved between maximum inspiration and maximum expiration.
Remember: inspiratory reserve is measured beyond the end of a normal inspiration.

Question 7

Multiple choiceMedium1 mark

In a plant, the rate of water loss from leaf-cell walls increases. Which change in the xylem and role of cohesion are expected?

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Answer: B. Water loss from leaf-cell walls draws water out of the xylem through the cell walls, increasing tension (making the pressure potential more negative). Cohesion keeps water molecules connected in a continuous column, allowing this tension to draw water upward.

A: reverses the direction of water movement, so it incorrectly predicts reduced tension.
C: has the correct movement and tension but reverses the role of cohesion.
D: gets the water movement right but reverses the pressure change; tension is negative pressure potential.

Remember: transpiration creates tension, while cohesion maintains the continuous water column.

Question 8

Multiple choiceEasy1 mark

A terrestrial region has high temperatures throughout the year and very low rainfall in every month. Which statement(s) identify a biome likely to develop there?

I. A hot desert
II. A tropical forest
III. A tundra

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Answer: B. Hot deserts are characterized by high temperatures and very low rainfall, so the stated climate makes a hot desert likely.

A: adds II by treating high temperature alone as sufficient for tropical forest, despite the very low rainfall.

C: includes II, which requires high rainfall, and III, which is characterized by low temperatures.

D: accepts both tropical forest and tundra; the low rainfall excludes the former, and the high temperatures exclude the latter.

Remember: use both temperature and rainfall to distinguish biomes.

Question 9

Multiple choiceMedium1 mark

The table shows a molar-area index (molar grinding-surface area divided by combined incisor and canine area), measured in the same way for each skull. Diets of the living reference hominids are known from observations. Which inference about the fossil skulls is supported by the data?

SkullDietMolar-area index
Homo sapiens (living reference)Omnivorous1.2
Living hominid referenceHerbivorous2.4
Homo floresiensis (fossil)Unknown1.3
Paranthropus robustus (fossil)Unknown2.3
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Answer: C. The reference skulls associate a lower molar-area index with omnivory and a higher index with herbivory. The index for Homo floresiensis (1.3) is nearer the omnivorous reference (1.2), while that for Paranthropus robustus (2.3) is nearer the herbivorous reference (2.4).

A: reverses the relationship between the index and the reference diets.
B: correctly associates Paranthropus robustus with the herbivorous reference but assigns the lower-index Homo floresiensis to herbivory.
D: correctly associates Homo floresiensis with the omnivorous reference but assigns the higher-index Paranthropus robustus to omnivory.
Remember: comparisons with observed living species can support, but do not prove, dietary inferences from fossil dentition.

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