Question 1

Paper 2Medium6 marks

Nitric oxide is oxidized by oxygen to form nitrogen dioxide:

2NO(g) + O₂(g) → 2NO₂(g)

Initial rates were measured at 298 K.

Trial[NO] / mol dm⁻³[O₂] / mol dm⁻³Initial rate / mol dm⁻³ s⁻¹
10.02000.01002.40 × 10⁻⁴
20.04000.01009.60 × 10⁻⁴
30.02000.02004.80 × 10⁻⁴

At 308 K, an experiment with [NO] = 0.0200 mol dm⁻³ and [O₂] = 0.0100 mol dm⁻³ gave an initial rate of 3.60 × 10⁻⁴ mol dm⁻³ s⁻¹. Assume the rate equation is unchanged between these temperatures.

(a)

Determine the order of the reaction with respect to NO and O₂.

[2]
(b)

Write the rate equation for the reaction.

[1]
(c)

Calculate the rate constant, k, at 298 K, including its units.

[2]
(d)

State which temperature has the larger value of k, using the measurements to justify your answer.

[1]

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