Answer: A. For a nuclide, the proton number is $Z$ and the neutron number is $A-Z$ a $2+$ charge means two fewer electrons than protons. Thus $p=29$ $n=65-29=36$ and $e=29-2=27$

B: adds 2 to the proton number when finding electrons, reversing the charge effect.
C: uses the electron count instead of the proton number in $A-Z$ giving 38 neutrons.
D: assumes the ion has the same number of electrons as a neutral copper atom, ignoring its charge.

Remember: ion formation changes the number of electrons, not the nucleus.