Question 1

Paper 1, no calculatorHard6 marks

For n∈Zn\in\mathbb Z define

Sn=(n+1)5+(n−1)5.S_n=(n+1)^5+(n-1)^5.

A student conjectures that SnS_n is divisible by 3232 for every odd integer nn

(a)

Calculate S1S_1 directly.

[1]
(b)

Starting from SnS_n prove the identity

Sn≡2n5+20n3+10nS_n\equiv 2n^5+20n^3+10n

for all n∈Zn\in\mathbb Z Use == between successive expressions and ≡\equiv for the final identity.

[2]
(c)

Hence prove the student’s conjecture for every odd integer nn

[3]

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