IB Maths AI HL Topic 5: Calculus questions

Exam-style questions in the shape of Paper 1 and Paper 2, with full markschemes. Read the markscheme, or type, photograph or draw your answer and get it marked.

Question 1

Paper 2Medium14 marks

A small mass moves vertically on a spring. For t≥0t\geq 0 its displacement yy metres from its equilibrium position is modelled by

y(t)=0.32sin⁡(1.4t+0.30),y(t)=0.32\sin(1.4t+0.30),

where tt is measured in seconds and angles are in radians. This is a model of simple harmonic motion.

(a)

State the amplitude and period of the motion. Calculate the displacement of the mass at t=0t=0 giving your answer to three significant figures.

[3]
(b)

Show that

d2ydt2=−0.6272sin⁡(1.4t+0.30),\frac{d^2y}{dt^2}=-0.6272\sin(1.4t+0.30),

and hence show that

d2ydt2=−1.96y(t).\frac{d^2y}{dt^2}=-1.96y(t).
[3]
(c)

Determine the time of the first stationary point after t=0t=0 Use the second derivative test to classify this point.

[4]
(d)

Using your result from part (b), determine the time of the first point of inflexion after t=0t=0 State the concavity immediately before and after this point, and interpret the point in terms of the mass's motion.

[4]

Question 2

Paper 2Medium13 marks

A landscape designer models the vertical profile of a section of a footpath by

h(x)=0.009x3−0.25x2+1.7x+2.5,0≤x≤20,h(x)=0.009x^3-0.25x^2+1.7x+2.5,\qquad 0\leq x\leq20,

where xx is the horizontal distance, in metres, from the start of the section and h(x)h(x) is the height, in metres, above a reference level.

Consider the point on the profile where x=8x=8

(a)

Calculate the height of the profile at this point.

[2]
(b)

Show that

h′(x)=0.027x2−0.50x+1.7.h'(x)=0.027x^2-0.50x+1.7.
[2]
(c)

Determine the equation of the tangent to the profile at x=8x=8 giving your answer in the form h−h(8)=m(x−8)h-h(8)=m(x-8)

[3]
(d)

Determine the equation of the normal to the profile at x=8x=8 in the same form. Give its gradient to 3 significant figures.

[3]
(e)

Use your GDC to find the coordinates of the other point, different from the point where x=8x=8 at which the tangent in part (c) meets the profile. Give your coordinates to 3 significant figures.

[3]

Question 3

Paper 1Medium6 marks

A nutrient-solution pump feeds a tank. During the first 6 minutes, its delivery rate is modelled by

q(t)=12tt2+9 mL min−1,q(t)=\frac{12t}{t^2+9}\text{ mL min}^{-1},

where tt is the time in minutes after the pump starts. Let V(t)V(t) be the volume, in mL, delivered by time tt with V(0)=0V(0)=0

(a)

By evaluating the definite integral for V(t)V(t) show that

V(t)=6ln⁡(t2+99).V(t)=6\ln\left(\frac{t^2+9}{9}\right).
[2]
(b)

Calculate V(6)V(6) giving your answer to 3 significant figures.

[1]
(c)

A warning light activates when 8 mL has been delivered. Use your answer to part (b) to establish that the light activates before 6 minutes, and hence determine the time at which it activates. Give your answer to 3 significant figures.

[3]

Question 4

Paper 1Medium6 marks

Figure 1 shows the graph of y=4xsin⁡(x2)y=4x\sin(x^2) for 0≤x≤π0\leq x\leq\sqrt{\pi} Angles are measured in radians. The shaded region is bounded by the curve and the xx-axis.

00.511.5√π20123456xy
(a)

Write down the upper limit represented by the shaded region.

[1]
(b)

Find ∫4xsin⁡(x2) dx\displaystyle\int 4x\sin(x^2)\,dx

[2]
(c)

Hence find the exact xx-coordinate that divides the shaded region into two equal areas.

[3]

Question 5

Paper 2Medium6 marks

A pump transfers liquid into a container. For t≥0t\geq 0 its flow rate is modelled by

q(t)=2te−t2 L min−1,q(t)=2t e^{-t^2}\ \text{L min}^{-1},

where tt is the time in minutes since the pump starts. Let V(t)V(t) litres be the total volume transferred by time tt

(a)

Show that V(t)=1−e−t2V(t)=1-e^{-t^2}

[2]
(b)

Calculate the volume transferred in the first 1.51.5 minutes. Give your answer to three significant figures.

[1]
(c)

Determine the time at which 0.800.80 L has been transferred. Explain why any other mathematical solution is not relevant.

[3]

Question 6

Paper 2Medium7 marks

A laboratory monitors a culture of cells. Its population, yy is measured in thousands of cells, and tt is measured in hours. The rate of change of the population is modelled by

dydt=0.06y(14−y).\frac{\mathrm{d}y}{\mathrm{d}t}=0.06y(14-y).

The table summarizes the slopes in the slope field for this model. Each entry is the value of dydt\frac{\mathrm{d}y}{\mathrm{d}t} at the point given by its row and column. Slopes are in thousands of cells per hour.

yyt=0t=0t=0.5t=0.5t=1t=1
0000
72.942.942.94
111.981.981.98
14000
18−4.32-4.32−4.32-4.32−4.32-4.32
(a)

Show that the slope of the field at (t,y)=(0,9)(t,y)=(0,9) is 2.72.7

[2]
(b)

A culture has y=9y=9 at t=0t=0 Use the gradient at this point to estimate its population at t=0.5t=0.5

[2]
(c)

Use the slope field to decide whether your estimate in part (b) is likely to be greater or less than the modelled population at t=0.5t=0.5 Justify your answer, and state the population towards which the field predicts the culture will tend over a long time.

[3]

Question 7

Paper 2Medium7 marks

In a reserve, the prey and predator populations are represented by indices xx and yy measured in hundreds of animals. The time tt is measured in years after monitoring begins. The populations are modelled by

dxdt=0.8x−0.04xy,dydt=0.02xy−0.6y,\frac{\mathrm{d}x}{\mathrm{d}t}=0.8x-0.04xy, \qquad \frac{\mathrm{d}y}{\mathrm{d}t}=0.02xy-0.6y,

with x(0)=20x(0)=20 and y(0)=5y(0)=5 A researcher uses Euler’s method with a step size of 0.50.5 years.

(a)

Show that the Euler estimate for x(0.5)x(0.5) is 2626 and find the corresponding estimate for y(0.5)y(0.5)

[3]
(b)

Hence, use one further Euler step to estimate x(1)x(1) and y(1)y(1)

[2]
(c)

A researcher claims that the predator population is decreasing at t=1t=1 since the estimate for y(1)y(1) is lower than that for y(0.5)y(0.5) Use the model to assess this claim.

[2]

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