Question 1

Paper 2Medium15 marks

A surveyor records the elevations of points on a mountain access route. In Figure 1, xx is the horizontal distance, in metres, from a reference point and yy is the elevation, in metres.

The existing straight road runs from AA to BB A proposed extension runs from BB to CC Point EE is the proposed starting point of a second access track, which is to be parallel to ABAB

The maximum acceptable gradient for a road is 18%18\% where gradient is the rise divided by the horizontal distance, expressed as a percentage.

050100150200250300350400450500700710720730740750760770780790800810x / my / mABCE
(a)

Calculate the gradient of ABAB as a percentage.

[2]
(b)

Show that the equation of ABAB is

y=2371375x+718.4.y=\frac{237}{1375}x+718.4.
[2]
(c)

Hence, find the horizontal distance from AA at which ABAB reaches an elevation of 750750 m. Give your answer to the nearest metre.

[2]
(d)

The second access track passes through EE and is parallel to ABAB

Write its equation first in the form y−y1=m(x−x1)y-y_1=m(x-x_1) then in the form y=mx+cy=mx+c Hence, find its elevation when x=400x=400 m. Give your answer to the nearest 0.10.1 m.

[6]
(e)

Calculate the gradient of BCBC as a percentage and determine whether the proposed extension meets the maximum acceptable gradient.

[3]

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