Question 1

Paper 2Hard10 marks

In a simplified Millikan oil-drop experiment, negatively charged drops are held stationary between parallel plates. The polarity is chosen so that the electric force on a drop is upward. Assume buoyancy and other forces are negligible. The potential difference between the plates is 400 V400\ \mathrm{V} and their separation is 4.00 mm4.00\ \mathrm{mm}

Drop A has mass 4.90×10−15 kg4.90\times10^{-15}\ \mathrm{kg} Further drops are measured using the same method. The uncertainty in each charge estimate, including that for drop A, is ±0.08×10−19 C\pm0.08\times10^{-19}\ \mathrm{C} An independently calibrated candidate value is e0=1.60×10−19 Ce_0=1.60\times10^{-19}\ \mathrm{C} treat its uncertainty as negligible.

DropMeasured charge magnitude / 10−19 C10^{-19}\ \mathrm{C}
B3.18
C4.79
D6.39
E8.01
F5.55
(a)

Show that the magnitude qq of the charge on a stationary drop is given by

q=mgdV,q=\frac{mgd}{V},

where mm is the drop mass, gg is gravitational field strength, dd is the plate separation and VV is the potential difference.

[2]
(b)

Calculate the magnitude of the charge on drop A. Give your answer in coulombs.

[2]
(c)

Using e0e_0 and your answer to (b), determine the nearest integer nn for each of drops A–E, where q≈ne0q\approx ne_0

[2]
(d)

A student claims that the results for drops A–E establish that e0e_0 is the smallest possible charge, while drop F disproves charge quantization. Evaluate this claim using the measurements and their uncertainties.

[4]

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