IB Biology HL Theme A: Unity and diversity questions

Exam-style multiple choice and written questions with full markschemes. Check multiple choice answers straight away, or type, photograph or draw a written answer and get it marked.

Question 1

Multiple choiceHard1 mark

For one star, a model places the Goldilocks zone—the orbital band where surface conditions could permit liquid water—at 1.20–2.00 × 10¹¹ m. A survey retains a site only if it is in this band, has liquid water and shows the expected solubility pattern for known hydrophilic and hydrophobic probes. Which site should be retained?

SiteOrbital distance / (10¹¹ m)Water observedHydrophilic probe in waterHydrophobic probe in water
A1.50LiquidDissolvedDissolved
B1.70IceNo liquid sampleNo liquid sample
C1.80LiquidDissolvedUndissolved
D2.20LiquidDissolvedUndissolved
Show answer and explanation

Answer: C. The modeled zone spans 1.20–2.00 × 10¹¹ m, so site C at 1.80 × 10¹¹ m is within it. Its sample is liquid, with the hydrophilic probe dissolved and the hydrophobic probe undissolved, matching water’s solvent properties. Many hydrophilic molecules dissolve in water, and most enzymes catalyse reactions in aqueous solution, so these observations support a possible medium for metabolism, but do not establish that life is present.
A: the location and liquid water fit, but dissolution of the known hydrophobic probe does not match the expected solvent pattern.
B: being in the zone does not make ice a liquid aqueous medium for enzyme catalysis.
D: the solvent observations fit, but 2.20 × 10¹¹ m is beyond the survey’s zone.
Remember: the Goldilocks zone makes surface liquid water possible; it does not guarantee water or life.

Question 2

Multiple choiceHard1 mark

A museum’s catalogue covers many species and must organize them for comparative studies while reflecting inferred ancestry. The table gives the branching sequence, from earliest split to latest, and current class assignments. A clade contains a common ancestor and all its descendants. Which proposal meets both aims?

InformationData
Branching sequenceS separates from P, Q and R; then R separates from P and Q; then P separates from Q
Current classesM: P and Q; N: R and S
Show answer and explanation

Answer: B. A clade contains a common ancestor and all its descendants. The branching sequence gives nested clades P+Q and P+Q+R (and the full set); R+S is not a clade because their common ancestor also has P and Q as descendants. Classification can still organize extensive diversity for comparison, while unranked clades avoid implying that fixed taxonomic ranks measure evolutionary divergence.
A: It assumes both traditional classes are clades; class N excludes P and Q even though they descend from the same ancestor as R and S.
C: It treats the limitation of fixed ranks as a reason to discard classification, although classification facilitates comparative study.
D: It assigns rank by group size; the branching pattern does not require nested clades to have class and order ranks.
Remember: clades express common ancestry, whereas taxonomic ranks are fixed categories.

Question 3

Multiple choiceHard1 mark

Researchers recorded responses to courtship displays between and within two species, then recorded the outcomes of resulting matings. Evolution is a change in heritable characteristics of a population. Which interpretation is supported?

PairingCourtship displays accepted (%)Matings producing viable offspring (%)Viable offspring that were fertile (%)
P × P849296
Q × Q819095
P × Q8880
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Answer: C. Courtship displays were accepted less often between species than within either species, indicating a behavioural barrier to mating. Although some interspecific matings produced viable offspring, none of the viable hybrids were fertile, so they could not pass alleles to later generations. The results indicate barriers to allele flow but do not show a change in heritable characteristics of a population over time.

A: Confuses viability with fertility; the hybrids were viable but could not reproduce.
B: Reverses the barrier stages: courtship affects mating before fertilization, while sterility occurs in hybrids.
D: Treats a difference between pairings as evidence of heritable change over time; the data do not establish that change.

Remember: Viable offspring can still be sterile and unable to transmit alleles to another generation.

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