Physics HL · Chapter 20: Electromagnetic Induction
20.1 Motional emf and Magnetic Flux
Develop induction from moving-conductor charge separation and connect it to magnetic-flux geometry.
Estimated time: 34 minutes
Charge Separation in a Moving Conductor
Take a conducting rod moving through a uniform magnetic field. Mobile charges in the rod have velocity with the rod, so each charge experiences a magnetic force q(v x B). That force pushes positive and negative charges toward opposite ends of the rod, creating a separation of charge and therefore a potential difference between the rod's ends.
The separation continues only until electric and magnetic effects balance. At equilibrium, an internal electric field opposes further charge drift. This is the mechanical origin of motional emf: motion through field geometry creates charge separation without any battery.
Deriving the Motional emf Formula
For a rod of length L moving at speed v perpendicular to uniform B, emf magnitude scales linearly with field, conductor length, and speed.
This equation can be read physically: stronger fields push charges harder, longer conductors give more separation distance, and faster motion increases magnetic force on each charge carrier. If any one factor doubles while the others stay fixed, induced emf doubles.
Direction is not included in the scalar expression, so keep direction logic separate. Use a consistent right-hand-rule workflow or flux-sign convention to determine which rod end becomes positive and therefore which direction conventional current would flow in a closed circuit.
Flux as Geometry: Phi = BA cos(theta)
Magnetic flux is not a force and not a field by itself; it is a geometric measure of how much field passes through a chosen surface. For uniform fields it is BA cos(theta), where theta is between the field direction and the surface normal. You can change flux by changing field strength, area, orientation, or any combination.
Simulation: Motional emf Rail Analyzer
Slide a conducting rod through a uniform field and inspect how area, flux, induced emf, current, and polarity update together.
Flux Phi
-0.038 Wb
dPhi/dt
-0.405 Wb/s
Induced emf
-0.405 V
Current
-0.184 A
Power
0.075 W
Rod polarity
- top, + bottom
Test Yourself
A rod of length 0.30 m moves at 4.0 m/s perpendicular to a 0.50 T field. Enter the induced emf magnitude.
Hint: Use epsilon = BLv with all quantities in SI units.