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Physics HL · Chapter 5: Rigid Body Mechanics

5.2 Torque and Rotational Equilibrium

Use line of action, torque ledgers, and interactive balancing to evaluate rotational equilibrium about chosen axes.

Estimated time: 34 minutes

Torque as Turning Effect

Torque measures how effectively a force can cause rotation about a chosen axis. Its magnitude depends on force size and perpendicular lever arm. A large force through the axis can create zero torque, while a smaller force far from the axis can produce significant rotation.

tau=Fd=rFsin(theta)tau = F d = r F sin(theta)

d is the perpendicular distance from the axis to the line of action of the force.

Sign conventions matter. Choose clockwise or counterclockwise as positive at the start and keep that choice throughout. Mixed sign conventions are the most common reason an otherwise correct setup fails to satisfy equilibrium conditions.

Static Equilibrium Conditions

A rigid body at rest requires both net force zero and net torque zero. The first condition prevents linear acceleration of the center of mass. The second prevents angular acceleration about the axis. If either condition fails, the body cannot remain fully static.

In ladder and beam problems, selecting a pivot can simplify the algebra by eliminating unknown reaction forces from the torque equation. This does not change the physics; it only changes which terms are easiest to calculate.

Axis Choice Strategy

Pick an axis through as many unknown forces as possible. Their moment arms become zero, and torque equations become cleaner.

Diagram-First Torque Mapping

In Tsokos-style beam and ladder questions, the fastest reliable method is diagram-first: sketch the axis, draw every force with its line of action, then convert the picture into a torque ledger. Treat each torque term as force times signed perpendicular arm. This is a diagrams-by-code mindset: the diagram is the data structure, and the equation is just its serialized form.

tauabout pivot=(±Fidi)=0\sum tau_{about\ pivot} = \sum (\pm F_i d_i) = 0

Assign each torque a sign from your chosen rotation convention before substituting numbers.

This approach also explains why pivot choice is a strategy, not a law. Different pivots produce different intermediate equations but the same physical result. If your chosen pivot makes unknown reactions disappear, your algebra becomes shorter while still preserving full mechanics.

Interactive Torque Balance

Use the simulation to vary pivot position, force magnitudes, and lever arms, then watch the net torque update. Aim for a near-zero net torque state and observe that many different force-distance combinations can satisfy equilibrium.

Simulation: Torque Balance Lab

Tune left and right forces and their moment arms around a pivot to achieve rotational equilibrium.

Torque Balance Lab

Left torque (CCW)

72.00 N·m

Right torque (CW)

72.00 N·m

Net torque

0.00 N·m

State

Rotational equilibrium

Statics diagram (bodies + forces + moments)

6.1 kg4.6 kgWₗ = 60 NWᵣ = 45 NR = 105 N1.20 m1.60 mClockwise and counterclockwise moments cancel.

Start with a symmetric pivot and compare a larger force at short arm to a smaller force at long arm. This mirrors the textbook wrench argument: turning effect depends on both factors, not force alone.

Simulation: Force-vs-Arm Tradeoff

Test equal-torque combinations by pairing stronger-shorter and weaker-longer force setups.

Torque Balance Lab

Left torque (CCW)

99.00 N·m

Right torque (CW)

99.00 N·m

Net torque

0.00 N·m

State

Rotational equilibrium

Statics diagram (bodies + forces + moments)

9.2 kg5.6 kgWₗ = 90 NWᵣ = 55 NR = 145 N1.10 m1.80 mClockwise and counterclockwise moments cancel.

Now move the pivot off-center and notice that available arm lengths change. The balancing condition is still zero net torque, but feasible solutions shrink on the short side and expand on the long side. This captures why support placement controls mechanical advantage.

Simulation: Off-Center Pivot Stress Test

Shift the pivot and re-balance while watching how asymmetric geometry changes the design space.

Torque Balance Lab

Left torque (CCW)

121.80 N·m

Right torque (CW)

121.54 N·m

Net torque

0.26 N·m

State

Rotational equilibrium

Statics diagram (bodies + forces + moments)

4.3 kg12.0 kgWₗ = 42 NWᵣ = 118 NR = 160 N2.90 m1.03 mClockwise and counterclockwise moments cancel.

Interpretation checkpoint: if one side feels impossible to balance, check whether you are limited by geometry instead of arithmetic. In real structures, this corresponds to not having enough lever arm to offset a load.

Test Yourself

A 25 N force acts 0.80 m from a pivot and a 20 N force acts on the opposite side. What arm length (m) must the 20 N force have for rotational equilibrium?

Hint: Set clockwise torque equal to counterclockwise torque.

Test Yourself

A force is doubled while its perpendicular arm is halved about the same pivot. What happens to its torque magnitude?

Hint: Use the product form tau = Fd.