Physics HL · Chapter 22: Quantum Physics
22.3 Compton Scattering and Photon Momentum Evidence
Use wavelength-shift measurements to show photon collisions obey particle-like momentum conservation.
Estimated time: 34 minutes
Collision Picture and Why Wavelength Increases
Compton scattering treats light-electron interaction as a two-body collision: an incident photon strikes a near-free electron, the photon leaves at a new angle with reduced energy, and the electron recoils with kinetic energy. Because the scattered photon has lower energy, its wavelength is longer. This effect is strongest for X-ray and gamma-ray wavelengths where photon energies are high enough for measurable shifts.
The key point is not only that energy changes, but that momentum-conservation equations with photon momentum p = h/lambda correctly predict angle-dependent wavelength shift. That is stronger than the photoelectric argument because it uses two-dimensional collision geometry rather than only threshold energetics.
Compton Shift Equation
Shift depends on scattering angle only; h/(m_e c) is the electron Compton wavelength.
Forward scattering (theta near 0 degrees) gives almost no shift because the photon continues nearly in its original direction and transfers little momentum. Backscatter (theta near 180 degrees) gives maximum shift because momentum reversal demand is largest. This angle control is exactly what experiments verify.
Energy Transfer Interpretation
After finding shifted wavelength, recover scattered photon energy from E' = hc/lambda'. Electron kinetic energy is then K_e = E - E'. Keeping units consistent matters because keV, pm, and SI joules are frequently mixed in one question. If the shift is tiny relative to original wavelength, only a small energy fraction goes into electron recoil.
Simulation: Compton Angle and Wavelength Shift
Sweep scattering angle and incident photon energy to inspect vector momentum geometry, wavelength shift, and electron recoil energy.
Momentum Vector Geometry
The wavelength increase depends only on angle through delta lambda = lambda_c (1 - cos theta), not on initial photon energy.
Incident Lambda
20.664 pm
Scattered Lambda
22.753 pm
Scattered Energy
54.492 keV
Electron K.E.
5.508 keV
Test Yourself
Two Compton-scattering experiments use different incident photon energies but the same scattering angle. Which statement is correct about delta lambda?