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Physics HL · Chapter 4: Linear Momentum

4.1 Newton's Second Law in Momentum Form and Impulse

Use F = dp/dt for changing-mass cases and interpret force-time area as impulse.

Estimated time: 31 minutes

Momentum Form of Newton's Second Law

The familiar expression F = ma is a special form that works directly when mass is constant. The broader statement is that net force equals the rate of change of momentum. This more general form handles cases where mass flow matters, such as rockets or material collecting on a moving surface.

Fnet=ΔpΔt,p=mv\vec{F}_{\text{net}} = \frac{\Delta \vec{p}}{\Delta t}, \qquad \vec{p} = m\vec{v}

When m is constant, this reduces to m * delta-v / delta-t.

A useful exam insight is that zero acceleration does not automatically imply zero net force when mass is changing. If an object keeps the same speed while its mass increases, its momentum still rises, so an external force is required to support that momentum increase.

Impulse as Momentum Change

Rearranging the momentum law over a time interval gives impulse: net force multiplied by contact time equals momentum change. Impulse is a vector in the same direction as net force. Graphically, impulse is the signed area under the force-time graph.

J=FavgΔt=Δp\vec{J} = \vec{F}_{\text{avg}}\,\Delta t = \Delta \vec{p}

For non-constant force, compute area under F-t to obtain impulse.

Why Longer Contact Time Reduces Peak Force

If a required momentum change is fixed, increasing contact time lowers average force. This is the design logic behind safety equipment: spread the same momentum change over more time to reduce damaging peak forces on people and structures.

Guided Practice: From Force-Time Shape to Final Speed

Many exam questions hide momentum change inside a force-time graph. A reliable sequence is: (1) compute signed area under F-t to get impulse, (2) set impulse equal to delta-p, and (3) solve for the missing speed with careful sign handling. Area above the time axis is positive and area below is negative.

Δp=t1t2F(t)dt(signed area pieces)\Delta p = \int_{t_1}^{t_2} F(t)\,dt \approx \sum (\text{signed area pieces})

For triangles and rectangles, geometric area is usually faster than calculus.

If mass is constant, write m(v_f - v_i) = impulse. If mass changes, keep momentum in m v form without forcing an acceleration method. This matches the chapter warning that F = ma is not the safest starting point when mass flow is involved.

Test Yourself

A 0.20 kg ball moving at +6.0 m/s rebounds at -4.0 m/s. If contact lasts 0.050 s, enter the magnitude of the average force in newtons.

Hint: Find delta-p first, then divide by contact time.

Test Yourself

A 3.0 kg cart starts from rest. A horizontal force-time graph is a rectangle of height 6.0 N from t = 0 to 4.0 s. Enter the cart's speed at 4.0 s.

Hint: Find impulse from area, then use impulse = delta-p.