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Physics HL · Chapter 20: Electromagnetic Induction

20.6 RMS Power and Transformer Links

Use RMS values for practical AC power and connect alternating flux to transformer voltage scaling.

Estimated time: 28 minutes

Why RMS Values Are Used

Instantaneous AC voltage and current oscillate, so practical ratings use RMS (root-mean-square) values. RMS corresponds to the DC value that would deliver the same average heating effect in a resistor. This is why mains ratings are RMS numbers, not peak numbers.

Vrms=V02,Irms=I02V_{\mathrm{rms}} = \frac{V_0}{\sqrt{2}},\qquad I_{\mathrm{rms}} = \frac{I_0}{\sqrt{2}}

These relations hold for pure sinusoidal waveforms.

Average power in a resistive AC load is P_avg = V_rms I_rms, while instantaneous power oscillates through the cycle. In sinusoidal resistive cases, average power is half the peak instantaneous power from the V0 and I0 product.

Transformer Principle from Induction

A transformer uses alternating current in the primary coil to create changing flux in a shared core. That changing flux links the secondary coil and induces emf there. No changing flux means no transformer action, which is why transformers require AC rather than steady DC in normal operation.

VsVp=NsNp,VpIpVsIs (ideal)\frac{V_s}{V_p}=\frac{N_s}{N_p},\qquad V_p I_p \approx V_s I_s\text{ (ideal)}

Step-up voltage implies step-down current in ideal power-conserving transfer.

In real transformers, copper losses, core losses, and leakage flux reduce efficiency below 100%, but turn-ratio logic remains the first prediction tool. Keep units and turn ordering consistent to avoid simple inversion mistakes.

Note

Transmission grids use high voltage and low current to reduce I^2R cable losses over long distances.

Simulation: AC Power and RMS Inspector

Use one generator waveform to compare peak values, RMS equivalents, instantaneous power, and cycle-averaged power.

NSCyan: v(t), Orange: p(t) over one cycle.

V0

147.781 V

Vrms

104.497 V

v(t)

138.868 V

i(t)

4.629 A

Irms

3.483 A

p(t)

642.813 W

Pavg

363.985 W

Period

20.000 ms

Test Yourself

An ideal transformer has Np = 500, Ns = 100, and primary voltage 230 V. Enter secondary voltage magnitude.

Hint: Apply Vs/Vp = Ns/Np.