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Physics HL · Chapter 22: Quantum Physics

22.1 Photons, Energy Quantisation, and the Photoelectric Start

Establish photon energy and momentum relations, then connect them to intensity and emission-rate reasoning.

Estimated time: 36 minutes

From Wave Frequency to Photon Energy

Classical electromagnetism correctly describes wave propagation, interference, and polarization, but quantum physics adds a second statement: electromagnetic radiation exchanges energy with matter in packets. Each packet is a photon with energy proportional to frequency. This does not erase wave behavior. It adds quantised interaction rules whenever light is emitted or absorbed.

E=hf,c=fλE = hf,\qquad c=f\lambda

Higher frequency means higher photon energy; shorter wavelength means higher frequency.

A useful operational interpretation is that changing light intensity at fixed frequency changes photon count per second, not energy per photon. That single distinction explains many exam traps. If frequency stays fixed, each photon carries the same hf regardless of whether the beam is dim or bright.

Photon Momentum and Radiation Pressure

p=Ec=hλp = \frac{E}{c}=\frac{h}{\lambda}

Photons carry momentum despite zero rest mass, so light can transfer impulse to surfaces.

When photons strike a surface, pressure appears from momentum transfer rate. Absorption transfers momentum p per photon; reflection transfers approximately 2p if reflection is near-normal and elastic. This is the microscopic basis of radiation pressure and why reflective sails can be more efficient than absorptive surfaces in propulsion concepts.

The scaling is linear in beam intensity: double intensity and momentum flux doubles. But wavelength still matters because photon momentum h/lambda changes with lambda. Shorter wavelength photons carry more momentum each, so for fixed power they arrive less frequently but each transfer event is stronger. These compensating trends are why explicit equation use is safer than intuition.

Why This Matters Before Photoelectric Details

Photoelectric emission is often taught as a standalone formula, but it is really one consequence of the same quantised transfer picture. If one electron absorbs one photon, the incoming energy per event is hf. Whether that event ejects an electron depends on whether hf can overcome surface binding energy. So photon-energy and photon-count logic must already be clear before stopping-voltage graphs make physical sense.

Simulation: Photon Energy, Momentum, and Surface Pressure

Tune wavelength, power, and absorption-vs-reflection mode to compare photon energy, flux, momentum transfer, and resulting pressure/force.

Beam-To-Surface Interaction

interaction plateincoming photonspressure from momentum transfer: 4.45e-4 Paforce on plate: 2.67e-7 N

Photon Energy

2.431 eV

Photon Momentum

1.30e-27 kg m/s

Photon Flux

1.03e+20 /s

Photons per ns

1.03e+11

Test Yourself

A monochromatic beam keeps the same wavelength, but its intensity doubles. Which statement is correct?